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(25/9)*x^2-((50/3)*x) = 0
(25/9)*x^2+(-50/3)*x = 0
25/9*x^2-50/3*x = 0
DELTA = (-50/3)^2-(0*25/9*4)
DELTA = 2500/9
DELTA > 0
x = ((2500/9)^(1/2)+50/3)/(2*25/9) or x = (50/3-(2500/9)^(1/2))/(2*25/9)
x = 6 or x = 0
x in { 0, 6 }
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